In Chapter 5 in NFPA 2001, edition 2018
There is a table, Table 184.108.40.206 Atmospheric Correction Factors.
¿What would be my correction factor if my equivalent altitude is over 14,000 ft?
In Table 220.127.116.11, the atmospheric correction factor is absolute enclosure pressure above sea level divided by absolute pressure at sea level.
You can interpolate the above table for 14000 ft above sea level.
The equation for finding the interpolated value can be written as y = y1 + ((x – x1)/(x2 - x1) * (y2 - y1))
X = 14,000 ft
X1 = 10,000 ft
X2 = 15,000 ft
Y = absolute pressure (psi) at 14,000 ft
Y1 = 10.108 psi
Y2 = 8.297 psi
Plug in the numbers and calculate.
Y = 10.108 + ((14000-10000)/(15000-10000) * (8.297-10.108)
Y =8.659 psi at 14,000 ft
Calculate the atmospheric correction factor = 8.659 / 14.696 = 0.589 at 14,000 ft
Thank you Milton,
Great and useful information.
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